(6x^2-1)+(4x^2-3)=5

Solution for (6x^2-1)+(4x^2-3)=5 equation:

Simplifying
(6x2 + -1) + (4x2 + -3) = 5

Reorder the terms:
(-1 + 6x2) + (4x2 + -3) = 5

Remove parenthesis around (-1 + 6x2)
-1 + 6x2 + (4x2 + -3) = 5

Reorder the terms:
-1 + 6x2 + (-3 + 4x2) = 5

Remove parenthesis around (-3 + 4x2)
-1 + 6x2 + -3 + 4x2 = 5

Reorder the terms:
-1 + -3 + 6x2 + 4x2 = 5

Combine like terms: -1 + -3 = -4
-4 + 6x2 + 4x2 = 5

Combine like terms: 6x2 + 4x2 = 10x2
-4 + 10x2 = 5

Solving
-4 + 10x2 = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 10x2 = 5 + 4

Combine like terms: -4 + 4 = 0
0 + 10x2 = 5 + 4
10x2 = 5 + 4

Combine like terms: 5 + 4 = 9
10x2 = 9

Divide each side by '10'.
x2 = 0.9

Simplifying
x2 = 0.9

Take the square root of each side:
x = {-0.948683298, 0.948683298}